Question

solve the system of equations:
x+2y + z=1
2x+3y+2z=0
-x-3y+3z=1
*****Please Help!!!*****

Answer 1

so like a first step assum first and 3rd equation so than will be eliminated the terms of x

hope you can continue it

Answer 2

A) x+2y + z=1
B) 2x+3y+2z=0
C) -x-3y+3z=1
Adding equations A & C
-y +4z = 2
Multiplying equation by -1
y -4z = -2
y = (4z -2)

Inputting this in equation A
x + 2*(4z-2) + z =1
x + 8z -4 + z = 1
x + 9z = 5 multiply by -2
D) -2x -18z = -10


Inputting y = (4z -2) in equation B
2x+3y+2z=0
2x + 3*(4z-2) + 2z =0
2x + 12z -6 + 2z = 0
E) 2x +14z = 6

Adding equation D and E
-4z = -4
z = 1

Now you have 1 of the 3 variables.