Question

How can consensus theorem be applied to prove A'B+B'C+C'A=AB'+BC'+CA'?
Guys, please help me with this prob ASAP...
Thnx in advance....

Answer 1

A'B+B'C+C'A=A'B(C+C')+(A+A')B'C+A(B+B')C'=
A'BC+A'BC'+AB'C+A'B'C+ABC'+AB'C'=AB'(C+C')+(A+A')BC'+A'(B+B')C=
AB'+BC'+A'C

Answer 2

Keep in mind that A+A'=1; B+B'=1;C+C'=1

Answer 3

Thnx Carlos...