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OpenStudy (anonymous):
What is the equation in point-slope form of the line passing through (–2, 1) and (4, 13)?
please help me
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OpenStudy (ivettef365):
what is the slope ?
OpenStudy (anonymous):
y – 1 = –2(x – 4)
y – 1 = 2(x + 2)
y – 13 = –2(x + 2)
y – 13 = 2(x + 4)
OpenStudy (ivettef365):
do you know what is the slope ?
OpenStudy (anonymous):
no I dont unfortunatly
OpenStudy (ivettef365):
ok slope you use formula
y2 - y1
------
x2 - x1
you have points (-2,1) and (4,13) , can you plug in on formula
(x1,y1) (x2,y2)
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OpenStudy (anonymous):
i still dont get how to get to the answer after pluggin in and solving
OpenStudy (ivettef365):
13 - 1 12
----- = ---- = 2
4 + 2 6
so the slope = 2
OpenStudy (ivettef365):
the formula for the equation in point slope form
is y- y1 = m(x-x1) you have m= slope = 2, use points (-2,1) for (x1,y1)
what do you get ?
OpenStudy (ivettef365):
can you plug numbers in this formula, that will give you answer
OpenStudy (anonymous):
y – 1 = 2(x + 2) ?
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OpenStudy (ivettef365):
correct
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