Question

What is the equation in point-slope form of the line passing through (–2, 1) and (4, 13)?

y – 1 = –2(x – 4)

y – 1 = 2(x + 2)

y – 13 = –2(x + 2)

y – 13 = 2(x + 4)

2.What is the equation of the line passing through (–3, 6) and parallel to the line y = 4x – 2 in standard form?

x – 4y = –18

x + 4y = 18

4x – y = –18

4x + y = 18
PLEASE HELP IM IN A HURRY I'LL GIVE A MEDAL

Answer 1

I already gave you answer for the first one, did you get it??

Answer 2

FInd the slope between the two points first:

m = y2-y1/x2-x1

and plug that into y-y1=m(x-x1)

Answer 3

No i didn't ivette

Answer 4

y – 1 = 2(x + 2) ? right

Answer 5

correct

Answer 6

for the second equation what is the slope on equation y=4x-2

Answer 7

the slop of y=4x-2 is 4/1