Question

Simplify: n^2+3n+2 n+1
----------- divided by -----
2 2(n+2)

Answer 1

when you divide just switch the second equation and multiply so you have

n^2 + 3n +2 2(n+2)
------------ . ----- ----
2 n+1

Answer 2

ok

Answer 3

solve for n^2+3n+2, do you know how to

Answer 4

noo

Answer 5

that would be (n+2)(n+1) just because 2x 1 = 2 and 2+1 = 3

so you have

(n+2)(n+1) 2(n+2)
---------- . -------
2 (n+1)

Answer 6

now what can you convert to 1

Answer 7

1 2 +2
-- . -------
2 1 ?

Answer 8

{(n^2+3n+2)/2}*{2(n+2)/(n+1)}
={(n^2+2n+n+2/2}*{2(n+2)/(n+1)}
={(n(n+2)+1(n+2)}*{2(n+2)/(n+1)}
={(n+1)(n+2)}*{2(n+2)/(n+1)}
=2*{(n+2)^2}

Answer 9

you can cancel the (n+1) from top and bottom and you can cancel the "2"

so you have

n+2 n+2
---- x ------
1 1

Answer 10

now multiply and you have (n+2)^2 or you can write the answer as
(n+2)(n+2) = n^2 +4n +4