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Mathematics 22 Online
OpenStudy (anonymous):

cos pi/2= sin @dumbcow @Psymon help please!!

OpenStudy (psymon):

= sinx?

OpenStudy (anonymous):

i guess thats what needs to be found.

OpenStudy (psymon):

Well, we can assume that there's an x you missed or that wasn't written in the question, lol.

OpenStudy (anonymous):

alright

OpenStudy (psymon):

So what is cos pi/2?

OpenStudy (anonymous):

0

OpenStudy (psymon):

Alright. So when is sinx equal to 0?

OpenStudy (anonymous):

pi?

OpenStudy (psymon):

And 0.

OpenStudy (anonymous):

alright

OpenStudy (psymon):

Thats all there is to it, lol.

OpenStudy (anonymous):

so the answer is either pi or 0?

OpenStudy (psymon):

Well, its both.

OpenStudy (anonymous):

ohhh okay. so what if we had sin pi/2=cosx?

OpenStudy (anonymous):

when does cos=pi/2 right?

OpenStudy (psymon):

Well if it were the other way around, we would need to say that sin pi/2 = 1 and then find where cosx = 1

OpenStudy (anonymous):

okay so then what?

OpenStudy (psymon):

Well, where does cosx = 1. That would be all youd need to find

OpenStudy (anonymous):

2pi?

OpenStudy (anonymous):

i think the answer is sin(k*pi*x) where k is any integer including 0.

OpenStudy (anonymous):

@Psymon so the answer is 2pi or what @Euler271 said?

OpenStudy (anonymous):

2pi=1 tho...

OpenStudy (psymon):

Well, cos x = 1 at 0

OpenStudy (anonymous):

answer is actually sin(k*pi) not sin(k*pi*x)

OpenStudy (anonymous):

well my answer choices are these 3pi/2 none of these 2pi pi/2 pi

OpenStudy (psymon):

Oh, he's looking at the original question. Yeah, cos pi/2 = sinx means x = 0 + kpi

OpenStudy (psymon):

So answer is pi then for you, lol.

OpenStudy (anonymous):

for the second problem or the first one?

OpenStudy (psymon):

For the first.

OpenStudy (psymon):

He was looking at your original problem, I was just confirming what he said, lol.

OpenStudy (anonymous):

okay so what about the second problem?

OpenStudy (psymon):

You were trying to find when cosx = 1, which is only at 0.

OpenStudy (anonymous):

so its pi for both?

OpenStudy (psymon):

No, its 0 for the 2nd one.

OpenStudy (anonymous):

it's sin(2pi) and sin(pi) in those options. but the real answer is sin(kpi)

OpenStudy (anonymous):

zero isnt a option so i put none of these?

OpenStudy (psymon):

Well, cosx = 1 only at 0. Technically, itd be 0 +2kpi. So if 2pi is an option then put that.

OpenStudy (anonymous):

2pi is a option @psymon but is that the right answer

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