Help please! ill reward a fan and medal! Question is below!
OA=OB ( Think..why?) angles opposite to equal sides are equal Now you can solve :)
still confused...
trying to find the angle, not the segment.
which part?
can you go over it?
because you gave OA=OB, angles need 3 points....
I was talking about the side OA and OB they are equal in length
does that mean theyre equal angles?
Yes! angles opposite to equal sides in a triangle are equal
Did you figure out why OA=OB?
i got 53.5 for the angles.
and no.
and that answer is on my question, is that correct ???
ankit?
no rewarding without a conclusion...
@jim_thompson5910
We have a circle with center at O, and diameter AC. We have arc AB and arc AC. Arc AB is 73° because it is subtended by the central angle AOB. Since the diameter is a straight angle, ∠AOB + ∠COB = 180°. Thus ∠COB = 107°, since ∠AOB = 73°. This implies that arc BC is 107°. One of the properties, is that an inscribed angle is exactly one-half of the central angle iff both the inscribed angle and the central angle are subtended by the same arc. If you observe, you notice that the inscribed angle ∠CAB and the central angle ∠COB are both subtended by arc BC. Thus by the theorem stated above, ∠CAB must be exactly one-half of ∠COB. half of 107 is 53.5. Therefore ∠CAB is 53.5°
calculas, youre amazing. thanks. i might have a few more questions. May you help me?
Yes I may.
But only if you spell calculus correctly. LOL
OH! Calculus!
Very Good!
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