Question

Someone please answer my previous question!! I'll reward and fan.

Answer 1

whats your previous question

Answer 2

A racket ball is struck in such a way that it leaves the racket with a speed of 4.81m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 1.93m from the racket. Find the height of the racket ball when it left the racket.

Answer 3

ok we cant just give answers we have to help you so you can do it next time now do you know how to calculate this?

Answer 4

@Paynesdad

Answer 5

No. Thats why I'm here.

Answer 6

My guess it there is a problem very similar to this one in the lesson. Usually there is in this kind of problem.

Answer 7

The answer is .789m

Answer 8

Well there are a couple of ways to approach this problem... but again. It is most likely based on an example in the lesson.

Answer 9

Without that problem in front of us, it is kind of hard to guide you in the right direction. Have you looked back through the lesson?

Answer 10

we need to get the time it took for the ball to hit the ground
horizontal speed is independent from gravity and thus is not affected by it and thus the velocity(h) at which it left the racket is constant 4.81(m/s) and it goes a distance 1.93m
d = r*t
t=d/r
t = 1.93/4.81

the equation for distance when we have acceleration and time is
D = (1/2) gt^2
so
D = (1/2)(9.8)(1.93/4.81)^2= .789

Answer 11

@rkscott do you understand?