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Mathematics 22 Online
OpenStudy (anonymous):

Question below!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@calculusfunctions

OpenStudy (anonymous):

idk if thats a right angle or not.

OpenStudy (calculusfunctions):

Yes, ∠BAC is a right angle.

OpenStudy (jdoe0001):

I'd think so, it's, AC looks to me like a tangent

OpenStudy (calculusfunctions):

Tell me if you know how to proceed now.

OpenStudy (anonymous):

so would i just subtract 34 from 90?

OpenStudy (calculusfunctions):

No.

OpenStudy (anonymous):

im stumped.

OpenStudy (calculusfunctions):

OK, first draw the line segment OY. Now, if the measure of arc BY is 34°, then that implies only that the central angle ∠BOY is 34°.

OpenStudy (anonymous):

yes.

OpenStudy (calculusfunctions):

Do recall what I said in the previous example?

OpenStudy (anonymous):

id have to go back. :/

OpenStudy (anonymous):

Its 68 isnt it?

OpenStudy (calculusfunctions):

The central angle is twice the inscribed angle, or the inscribed angle is half the central angle, iff both the inscribed angle and the central angle are subtended by the same arc.

OpenStudy (calculusfunctions):

NO.

OpenStudy (anonymous):

im sorry. hard time understanding

OpenStudy (jdoe0001):

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OpenStudy (anonymous):

jow, i think thats the wrong oicture.

OpenStudy (anonymous):

mine looks different...

OpenStudy (anonymous):

jdoe*

OpenStudy (jdoe0001):

unfortunately, no, you see when they labeled that angle BY as 34 degrees, they really meant as calculusfunctions said, a CENTRAL ANGLE, as opposed to the angle from the vertex way down there but 34 degrees from the center of the circle

OpenStudy (calculusfunctions):

@chickennuggetsaregood do you notice that the central angle ∠BOY and the inscribed angle ∠BAY are both subtended by arc BY?

OpenStudy (anonymous):

yes...

OpenStudy (calculusfunctions):

OK so then if ∠BOY is 34°, then what must be the measure of ∠BAY?

OpenStudy (calculusfunctions):

@chickennuggetsaregood ??

OpenStudy (anonymous):

im super confused...

OpenStudy (calculusfunctions):

Where? Do you not understand the theorem or is it something else. You need to be more specific.

OpenStudy (anonymous):

This implies that arc BC is 107°. One of the properties, is that an inscribed angle is exactly one-half of the central angle iff both the inscribed angle and the central angle are subtended by the same arc. If you observe, you notice that the inscribed angle ∠CAB and the central angle

OpenStudy (calculusfunctions):

∠BOY = 34° is the central angle, correct?

OpenStudy (anonymous):

yes..

OpenStudy (anonymous):

wouldit be half of 34?

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