how do you graph
f(x)=-(x-1)^2+4

Question

how do you graph
 f(x)=-(x-1)^2+4

anonymous · Answer

basic graph is a parabola
this one opens down since the leading coefficient is negative (it is $-1$)
also you can see from the form that the vertex is $(1,4)$ so anchor it there

anonymous · Answer

@satellite73

anonymous · Answer

i dont kno how graph period

mathmate · Answer

You can graph $ x^2 $
the -1 coefficient means a reflection about the x axis,
the -1 is a translation to the right by 1 unit, and finally 
the +4 is a translation upwards by 4 units.
Put them all together will give you exactly what Satellite73 described.

anonymous · Answer

o yeah i fully understand, thank you fellas...lol

mathmate · Answer

|dw:1375753468870:dw|

anonymous · Answer

what is this? does it coordinate with my original problem?

anonymous · Answer

parabola that opens down looks like this |dw:1375753727716:dw|