Question

cos 6x - cos2x ?

Answer 1

Is that all it says?

Answer 2

No picture?

Answer 3

what is the answer?

Answer 4

Cos x -cos y use this formula

Answer 5

yes the formula
: -2sin 1/2 (a+b) sin 1/2 (a-b)

Answer 6

can you help me please?

Answer 7

Wat did they tell to find?

Answer 8

\[\cos(6x)-\cos(2x) = -2\sin(\frac{ 6x+2x }{ 2})\sin(\frac{ 6x-2x }{ 2 })\]

Answer 9

Yeah the same thing .. But is that all u had o find?

Answer 10

You can simplify it a bit but not more than that I would say.

Answer 11

product terms of

Answer 12

yes mandre, how to calculate that?

Answer 13

It depends on what they ask for. Do you have a value for x then you substitute for x.

Answer 14

Simplified it's -2sin(4x)sin(2x)

Answer 15

the choices are
a. -6sin^2 2x cos2x
b. -4sin^2 2x cos2x
c. -2sin^2 2x cos2x
d. -6cos^2 2x sin2x
e. -4cos ^2 2x sin2x

Answer 16

can you help me?

Answer 17

It will be b.
sin(4x) = 2sin(2x)cos(x)
So
-2sin(4x)sin(2x)
= -2sin(2x)sin(4x)
= -2sin(2x).2sin(2x)cos(2x)
= -4sin^2(2x)cos(2x)

Answer 18

Correction:
sin(4x) = 2sin(2x)cos(2x)

Answer is still right though.

Answer 19

oh, thank you very much :)