Question

help please work attached @amistre64

Answer 1

\[\large \large -5xy(2xy)^2\] You want to do the exponent.
(2xy)^2 = (2xy)(2xy)
Now do the FOIL method. Do you know how to do the FOIL method?

Answer 2

Hold on 1 min. I think I did something wrong.

Answer 3

Yeah. You can't use the FOIL method. Just multiply.

So, 2 * 2 = ?
x *x = ?
y * y = ?

Answer 4

4y^2x^2

Answer 5

Alright. Now your equation would look like: \[\large \large -5xy*4x^2y^2\] And just multiply it.

-5 * 4 = ?
x * x^2 = ?
y * y^2 = ?

Answer 6

-20x^3y^3

Answer 7

Good. So the answer to that is "Answer 4"

Answer 8

\[\large \large (4x^3y)^2\] You can't simplify anything in the parenthesis, so you next do the exponent.

So now it would become: \[\large \large (4x^3y)(4x^3y)\]

Answer 9

Now multiply em.

4 * 4 = ?
x^3 * x^3 = ?
y * y = ?

Answer 10

16x^9y^2

Answer 11

Hmm.
x^3 8 x^3 does not equal to x^9.

Answer 12

16x^6y^2

Answer 13

Yes. So the answer is, "Answer 2"

Answer 14

For number 3. just multiply them. What do you get?

Answer 15

4x^3y^4

Answer 16

Great. So the answer is, "Answer 1".
Now I believe you can do the rest of them. If you want to make sure that you did it correctly, just post your answer. :)

Answer 17

ok

Answer 18

wait how do i do the division probs??

Answer 19

For multiplication, you add the exponent, and multiply the bases.
But for division, you subtract the exponent, and divide the bases.
So if the exponent on the numerator is x^5. And the exponent on the denominator is x^3. Then you would do x^5 - x^3 = x^2.

Answer 20

ok thanks