Question

@ilfy214 @amistre64 @goformit100 @GoldPhenoix

Answer 1

Start with the inside! g(x) = √x
\[f(g(√16))\]
Then insert f(x) = x + 2
\[\sqrt{16} + 2\]

Answer 2

The square root of 16 is 4.
\[\sqrt{16} + 2\]
\[4 + 2\]
\[= 6\]

Answer 3

sorry my computer froxe and do i do that for part 1?

Answer 4

@ilfy214

Answer 5

Yes.

Answer 6

@ilfy214 what do i do for pat 2

Answer 7

Its similar..

Answer 8

Just don't plug in the 16!
\[f(g(x)) = \sqrt{x} + 2\]

Answer 9

so 16+2
4+2
=6 that what i do

Answer 10

That is Part I.
The one I just did above is for Part II

Answer 11

@ilfy214 so how do i determine itsrange and domain

Answer 12

Sorry! Here you go! http://www.wolframalpha.com/input/?i= √x+%2B+2

Answer 13

Domain:
\[x ≥ 0\]
Range:
\[y ≥ 2\]