Question

Graph the circle (x+2)^2+(y+1)^2=32.Label the center and at least 4 points on the circle. Please help! I think the center is (-2,-1) but I don't know how to get the points

Answer 1

@mathstudent55 help?

Answer 2

You read the center of the circle from the equation:
(x - a)^2 + (y - b)^2 = r^2
(a,b) will be the center where (a,b) are the (x,y) coordinates. Remember the minuses in the above formula. In your case it will be
(x-(-2))^2 + (x-(-1)^2 = 32
Take the Square root of 32 for your radius and there you have your circle.

Substitute x=0 into your formula to work out the y intercepts. Remember there will be 2 (if any, the circle can be away from the axes depending on the center).
Substitute y=0 for your x-intercepts.

You were actually almost there. You had the center. You just needed the radius.

Answer 3

You don't need the intercepts but it helps to check if your graph is in the right place.