Question

help please b^3+8b^2-20b/b-2

Answer 1

factor out b in numerator

Answer 2

so b^2+8b-20/2

Answer 3

no it's\[\frac{ b(b^2+8b-20) }{b-2 }\]

Answer 4

\[b^3+8b^2-20b/(b-2)?\]

Answer 5

ok

Answer 6

...and you are solving for b?

Answer 7

Remember to determine the domain- denominator must be different from 0

Answer 8

can u help me get the answer cus that didnt help any

Answer 9

\[b 3 +8b 2 −20b/(b−2)\]
b's cancel giving:
\[=b^3+8b^2+10\]

Answer 10

ok what about the -2

Answer 11

pull b^2
\[=b^2(b+8)+10\]

Answer 12

the b's cancel and it leaves -20/-2. which = +10

Answer 13

ohhh

Answer 14

Is that all you need help with? or do we need to go further?

Answer 15

so my answer is b2(b+8)+10

Answer 16

yes, or the first answer I gave. they are both the same. just one is broken down further.

Answer 17

ok so can u help me with 4 more