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Factor completely:-12x2 - 6x Select one: a. 6x(2x+1) b. 2x(6x -2) c. prime d. -6x(2x+1)
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damnn ur cute i know this is not math related xD
D.
Also prime doesn't sound like the right terminology to use here, perhaps irreducible over somthing, would make more sense, I am not really familiar with any abstract algebra though so yeah.
pull -6x from the equation and you get \[-6x(2x+1)\]
devide \[-12x^2-6x\] by \[-6x\] =\[(-12x^2)/(-6x)+(-6x)/(-6x)\] =−6x(2x+1)
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thank you but it is @romanortiz65
i mean what i said xD
so it is d
fallowing?
yes Factor Completely: a2+ 5a +ab Select one: a. (a+5)(a+b) b. a(a+5+b) c. (a+2)(a+3) d. prime
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yes. Do you understand why the answer is d?
yes
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