Question

Ben has a toy light saber and he wants to construct one proportionally smaller than his. The light on his is 33 in and the handle is 9 in.



If the light on the smaller version is 11 in, how long should the handle be?

4.5 in

3 in

4 in

6 in

Answer 1

To figure it out, solve the proportion:

\[\frac{33}{11} = \frac{9}{x}\]

Answer 2

how do i do that and sorry am really bad at math

Answer 3

First, reduce the expression 33/11...can you do that?

Answer 4

divide

Answer 5

Yes. What do you get after dividing?

Answer 6

3

Answer 7

Okay, good, so now we have

\[3 = \frac{9}{x}\]

Now we just need to continue solving for x. Any ideas on how to do that?

Answer 8

put the 3 on the bottom of 9

Answer 9

Okay, divide both sides by 3, yes. What do we do with the x?

Answer 10

Right now we have:

\[1 = \frac{9}{3x}\]

And we need to isolate x

Answer 11

Any ideas on how to do that?

Answer 12

no

Answer 13

To isolate x in this case, multiply both sides by x:

\[x = \frac{9}{3}\]

Now all you have to do is divide 9/3 to get the value for x

Answer 14

3

Answer 15

Yes, so x = 3

Answer 16

so x =3

Answer 17

thx