x^2 - 10^x + 16 = -5

Can someone write this out in standard form and show their work. I had trouble learning this during the year and would like to be prepared.

Question

x^2 - 10^x + 16 = -5

Can someone write this out in standard form and show their work. I had trouble learning this during the year and would like to be prepared.

anonymous · Answer

I am pretty sure all you have to do to put that in standard form is to get one side to equal 0 ...so just add 5 to both sides of the equation

anonymous · Answer

Thank you so Paynes!

wolf1728 · Answer

x² -10x +21 = 0
by quadratic formula
a = 1 b=-10 c=21

x = [-(-10) ±sqrt(100 - 4 * 1 * 21) / (2*1)]
x = [10 ±sqrt(16)/2]
x = [10 +4 / 2] = 7

x = [10 -4 / 2] = 3