Question

Use the x-intercepts to find the intervals on which the graph of f is above and below the x-axis.

f(x) = (x - 3)^2(x + 4)^2

Answer 1

The first step would be to find the \(x\)-intercepts, which occur when \(f(x)=0\). So, solve for \(x\):
\[(x-3)^2(x+4)^2=0\]

Answer 2

(x-3)^2(x+4)^2>=0 for all x

Answer 3

the question does not make sense. the function is never below the x-axis and its ON the x-axis at 2 points. But the question just asks when is it above and when is it below.