Question

How does one solve sin(2x)=sqrt(3)/2? Basically, I am unsure how to approach a multiple within the sin definition?

Answer 1

use sinx = sina
then
x= n(pi) + )(-1)^n (a) wher n is any integer...

Answer 2

so
\[2x=sin^{-1}(\frac{\sqrt{3}}{2})\]