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Solve ln (x-4) < 6 and solve the inequality 3^2n less then or equal to 1/81
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\[\ln(x)=y\iff e^y=x\] and since both are strictly increasing \[\ln(x)<y\iff x<e^y\]
in your example \[\ln(x-4)<6\iff x-4<e^6\]
what i put down as my answer before was x < e^6 +4 is that wrong?
you are right
so that answers correct? Thanks!
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yes as for the next one, note that \(\frac{1}{81}=3^{-4}\)
so is that the answer or how i would begin to solve it?
\[3^{2n}<3^{-4}\iff 2n<-4\iff n<-2\]
I'm a bit confused, so the answer would be n <-2 ?
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yes, that is the answer
Thanks for all of your help!
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