Solve the equation Quantity x plus 1 all over 3 = 2 for x. Please show your work and solution.
so you have x+1 ---- = 2 3
\[\frac{x+1}{3}=2\]??
Follow these steps: 1) Multiply both sides by 3 2)subtract both sides by 1
1) multiply both sides by 3 ) subtract 1 from both sides
idk how to do that
i don't believe you what is \(3\times 2\) ?
6
\[\frac{x+1}{3}=2\] \[\frac{x+1}{3}\times 3=2\times 3\]\[\frac{x+1}{\cancel{3}}\times \cancel{3}=2\times 3\] \[x+1=6\]
i figured you could multiply 2 times 3 and get 6, maybe what wasn't clear is if you multiply the left side by 3, the denominator goes, leaving only \(x+1\) on the left
so that's the answer?
not quite, almost though what number would you add one to in order to get 6 ?
Hope this will let you understand what you should be doing on this problem .. ( X + 1) / 3 = 2 2. Multiply both sides of the equation by 3 [(X+1)/3] * 3 = 2 * 3 3/3 = 1, and 1 times anything is that thing itself, so (X+1) * 3 /3 = X+1 And 2 * 3 = 6, of course. X + 1 = 6 3. Subtract 1 from both sides to give the variable, X, by itself X+1 - 1 = 6 - 1 X + 0 = 5 X = 5
@nunncm ??do you understand know ?
yeah thankss
could you give me a best response star pleas @nunncm
thanks
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