Question

what is the equation of a line that is perpendicular 2x-3y=5 that pases through the point (2,-1)

Answer 1

Put the equation of the line into slope form by isolating the y.
y=2/3x-5/3
To find the slope of a line perpendicular to this one you find the opposite reciprical or in this case:
-3/2
Plug in the points you know and the slope into this formula:
(y-y1)=m(x-x1)
where m=slope
x1=x coordinate of a known point
y1= y coordinate of a known point
in this case we have
(y-(-1)=-3/2(x-2)
y+1=-3/2x+3
y=-3/2+2

Answer 2

get it?