Which of the following equations can be used to find a woman's present age is she is now 6 times as old as her son and next year her age will be equal to the square of her son's age?
A. 6w+1=w^2+1
B. 6(w+1)=w^2+1
C. 6(w+1)=(w+1)^2
D. 6w+1=(w+1)^2
E. w+6=(w+1)^2

Question

Which of the following equations can be used to find a woman's present age is she is now 6 times as old as her son and next year her age will be equal to the square of her son's age?
A. 6w+1=w^2+1
B. 6(w+1)=w^2+1
C. 6(w+1)=(w+1)^2
D. 6w+1=(w+1)^2
E. w+6=(w+1)^2

agent0smith · Answer

Assuming w is her son's age, which is not very smart, because woman begins with w...:

6 times as old as her son and next year her age
means 6w+1 (add 1 for it being next year)  

the square of her son's age next year
w^2 + 1

anonymous · Answer

@agent0smith  next year, square of her son's age shouldn't be (w+1)^2?

agent0smith · Answer

That's what i thought i wrote, lol. It's 5:30am

anonymous · Answer

lol get some sleep man :) we need you

radar · Answer

Let w = woman's age now
then son's age is w/6 now.
w + 1 = woman's age next year
(w/6) + 1 = son's age next year.
Stated by problem:  w + 1 = ((w/6) + 1)^2
w + 1 =(w^2)/36 + ((2w)/6)) + 1     Multiply thru by 36
36w + 36 = w^2 + 12w + 36   subtracting 36 from both sides
36w = w^2 + 12w    Subtract 36w from both sides
0 =w^2 - 24w
w(w - 24) = 0
w =24 son = 24/6 = 4

radar · Answer

Next year woman will be 25 and son will be 5

radar · Answer

5^2 = 25
25=25

anonymous · Answer

Ok, thanks for helping me out!