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if x^2-y^2=100 and x-y=20,what is the value of x+y?
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\[x ^{2}-y ^{2}=100\] \[x-y=20\] \[x+y=?\]
(x+y)(x-y)=x^2-y^2 do you get this part?
@ineedhelpnow08
no....
well if you have an expression in the form of a^2-b^2, then you can factorise it as (a+b)(a-b)
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(a+b)(a-b) a^2+ab-ab-b^2 a^2-b^2
do you get it now?
5
oh..
so now we can replace x^2-y^2 with (x+y)(x-y) to get (x+y)(x-y)=100
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so like its (20)(x+y)=100?
since we know (x-y) = 20, we can write (x+y)(20)=100 (x+y)=100/20 x+y=5
do you get it now?
thanks!!
haha... good luck with these type of question..
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lol S.A.T are hard
haha.. you just gotta work harder...
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