Question

factor each problem completely:
see below:

Answer 1

\[3x ^{2}+10x+8\]

Answer 2

Factoring a trinomial of the form \(ax^2 + bx + c\):
1. If there is a common factor of all terms, factor it out.

Is there a common factor to all three terms?

Answer 3

I got a 6 and 4

Answer 4

Where?

Answer 5

(3) 1*3
(8) 2*4

Answer 6

= 4,6

Answer 7

4 and 6 add up to 10...middle number

Answer 8

answer that I got is (x+2)(3x+4)

Answer 9

The answer to the question above is that there is no common factor of the three terms of the trinomial.
Now we move to the next step of factoring:
2. Multiply ac.
ac = 3*8 = 24

Next step:
3. Come up with 2 factors of ac that add up to b.
In this case you need two factors of 24 that add up to 10.
I think you are up to here already.

4. Rewrite the trinomial withe the middle term broken up into two parts using the factors from step 3.
\(3x^2 + 4x + 6x + 8\)

5. Factor by parts. That means factor a common factor out of the first two terms, and factor a common factor out of the last two terms.

\(x(3x + 4) + 2(3x + 4) \)

6. Factor out the common term.

\( (3x + 4)(x + 2) \)

You are correct.

Answer 10

one question.