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(3)/(x)-(3)/(x+1)-(3)/(x+2)
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-3x^2+6/x^3+3x^2+2x
How though
first, solve [ 3/x - 3/x+1 ] get the LCD: x^2+x or simply cross-multiply. and you'll get 3/x^2+x, don't forget to distribute the minus sign to the second term in the numerator.
after solving the first two terms, you now subtract your answer to the third term 3/x+2. same procedure, LCD or cross-multiply. combine like terms, and you'll get -3x^2+6/x^3+3x^2+2x
Thank you so much!!(:
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no problem. keep on practicing. :)
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