Question

Can anybody please help me with this question?

Answer 1

This is a Physics question, isn't it? :P

Answer 2

no, it is from Algebra 2

Answer 3

check the attached pic once

Answer 4

I checked it...

Answer 5

ok, which part you want help wid ?

Answer 6

The questions that are given in the pic

Answer 7

I don't know how to solve them

Answer 8

familiar wid series parallel circuits ?

Answer 9

sort of...

Answer 10

cool its easy then, whats Rc here, I dont see that label anywhere in the pic ?

Answer 11

Rc I would assume its the parallel combination resistance of 12 and X

Answer 12

Rc = 12 || X

do u knw the formula for equivalent resistance for resistors in parallel ?

Answer 13

no :(

Answer 14

ok here is the formula :-

a || b = ab/(a+b)

Answer 15

12 || X = ?

Answer 16

12x/(12+x) right?

Answer 17

thats right ! thats the equivalent resistance of parallel combination of 12 and X

Answer 18

move to part 2

Answer 19

so only that for the first question right?

Answer 20

for total resistance,

since 3 is in series, you just need to add 3 to the answer you got for part1

Answer 21

yes, oly that for q1

Answer 22

how to add 3? 12x/12+x + 3 or ?..

Answer 23

yes simply add 3

12x
---- + 3
12+x

Answer 24

simplify if u want to

Answer 25

how should I simplify??? :(

Answer 26

make the denominators same

Answer 27

12+x is the denominator for both? and then...?

Answer 28

12x
---- + 3
12+x


12x 3(12+x)
---- + --------
12+x 12+x

Answer 29

now the denominators are same. so we can add the numerators

Answer 30

12x
---- + 3
12+x


12x 3(12+x)
---- + --------
12+x 12+x


12x + 3(12 +x)
-------------
12+x

Answer 31

simplify the numerator

Answer 32

15x+36/12+x right?

Answer 33

right

Answer 34

thats the equivalent resistance of circuit

R = 15x+36 / 12+x

Answer 35

for part3, you need to use below formula :-

V = RI

Answer 36

here,

V = 6
I = 1

just plugin the values in above formula

Answer 37

Thank you so muuuuch for everything!!!:)