need help Match the probability with the outcome if two number cubes are rolled 100 times. an even number appeared on at least one cube 76 times
anybody
the probability an even number appears on "at least" one cube is \(\frac{3}{4}\) is that more or less clear?
i need a percentage
@satellite73 not clear
nvm
that is not what i am asking we can turn any number in to a percent, move the decimal place over two the question is, it is clear that on any one throw, the probability you get at least one even number is \(\frac{3}{4}\)
so what are you saying
@dlearner think of it like this: it is the same as flipping a coin, half even, half odd (e, e, ) (e, o), (o, e) , (o,o) three out of four times you get at least one even
what would it be in percentage then ????
oh k
you are not close to done now you need to use the binomial with \(n=100, k=76, p=\frac{3}{4},1-p=\frac{1}{4}\)
then figure out the percentage by moving the decimal that is not really much of the problem
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