Question

Which of the following equations represents a perpendicular line to 6x - 2y = 20?

y = 3x + 2

y = -3x + 4

y equals one third x minus 3

y equals negative one third x minus 5

Answer 1

what's the slope of => 6x - 2y = 20?

Answer 2

Do I bring the 6x on the other side with the 20 ?

Answer 3

yes

Answer 4

isolate "y"

Answer 5

So it should look like -2y = -6x + 20 ?

Answer 6

yes, now divide each side by -2
so you can solve for "y"

Answer 7

y = 6/2x + 10 ?

Answer 8

\(\bf -2y = -6x + 20 \implies \cfrac{-2y}{-2}=\cfrac{-6x}{-2} + \cfrac{20}{-2}\)

Answer 9

So where do I go from there ?

Answer 10

well, what did you get for the slope for that one?

Answer 11

6/2x I Believe

Answer 12

would you say that 6/2 = 3?

Answer 13

yes if you divide ! but we are still left with 20/-2

Answer 14

well, woudl you say that 20/-2 = -10?

Answer 15

yes ! but y = 3x - 10 is not one of my answer choices thats what im trying to figure out .

Answer 16

\(\bf \cfrac{-2y}{-2}\cfrac{-6x}{-2} + \cfrac{20}{-2} \implies y = 3x-10\)

Answer 17

My answer choices are
y = 3x + 2

y = -3x + 4

y equals one third x minus 3

y equals negative one third x minus 5

Answer 18

so the slope for this equation is "3", as you can see from the slope-intercept form

any perpendicular line to this line, will have a NEGATIVE RECIPROCAL slope

what does that mean?

RECIPROCAL of 3
1/3

NEGATIVIZE that
-1/3

so any lines with that slope, are PERPENDICULAR to this one

Answer 19

So which one is the answer ? y = 3x + 2 ?

Answer 20

the line that has that slope in negative reciprocal form :)

Answer 21

so y equals negative one third x minus 5 is the answer ?

Answer 22

y = -1/3 x -5
^
slope

so, yes, -1/3 is the negative reciprocal of 3

Answer 23

Can I ask you another question real quick ?

Answer 24

ok

Answer 25

Is zero consider an even number ?

Answer 26

hmm, I'd say no

Answer 27

ok Thank You For Your Help .

Answer 28

yw