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Mathematics 15 Online
OpenStudy (anonymous):

Simplify Completely: Radical Expressions Help

OpenStudy (anonymous):

\[5x^2-21x-20 \div 5x^2-16x-16\]

OpenStudy (anonymous):

Its rational expressions

OpenStudy (anonymous):

First, factor the numerator and factor the denominator. Let's start with the numerator 5x^2 - 21x - 20 = ( ) ( )

OpenStudy (anonymous):

Can you figure out what goes in the ( )'s ?

OpenStudy (anonymous):

(5x+1)(x-20)?...

OpenStudy (cwrw238):

is it 5x2−21x−20÷5x2−16x−16 or (5x2−21x−20)÷(5x2−16x−16) ?

OpenStudy (anonymous):

(5x + 4) (x -5) will be your numerator

OpenStudy (anonymous):

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

For your denominator, 5x^2 - 16x - 16 factors into (x-4)(5x+4) Now it should be obvious what you can cancel (5x-4) What's left is the answer.

OpenStudy (anonymous):

thanks

OpenStudy (cwrw238):

if you write the problem in one line use parentheses to avoid ambiguity

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