Question

Find the exact value of the radical expression in simplest form.
r times the square root of r − 3 times r times the square root of r + 4 times r times the square root of r

2r

2 times r times the square root of r

2 the square root of r

the square root of r

Answer 1

You'd be better off learning how to use the equation editor... that way people don't have to guess at what your wordy expressions are

\[\Large r \sqrt {r-3} *r \sqrt{r+4} * r * \sqrt r\]

I have no idea, to be honest... "r times the square root of r − 3 times r times the square root of r + 4 times r times the square root of r" this is way too hard to interpret.

Answer 2

\[r \sqrt{r}-3r \sqrt{r}+4r \sqrt{r}\]

Answer 3

combine like terms or factor out the \(\sqrt{r}\) same thing really

Answer 4

Thank you. Make sure you use it everytime from now on.

Just combine like terms or factor as satellite said... they all have a sqrt r.

\[\Large r \sqrt{r}-3r \sqrt{r}+4r \sqrt{r} = \sqrt r (r - 3r +4r)\]

Answer 5

\[2r \sqrt{r}?\]

Answer 6

Yep.

Answer 7

thank you! can you help me with one more?

Answer 8

Find the exact value of the radical expression in simplest form.
\[\sqrt{16y^3}-\sqrt{y^3}\]

Answer 9

a) \[3y \sqrt{y} b) 3y^2\sqrt{y} c) 4y^2\sqrt{y} d) 4y \sqrt{y}\]

Answer 10

\[\Large \sqrt{16y^3}-\sqrt{y^3} = \sqrt{16*y^2 *y}-\sqrt{y^2*y}\]
\[\Large \sqrt{16} \sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y}\]

Answer 11

is it D?

Answer 12

the square root of 16 is 4

Answer 13

Simplify everything here as much as you can \[\Large \sqrt{16} \sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y}\] you know sqrt16 is 4, so \[\Large 4\sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y}\]What else can you simplify?

Answer 14

\[\sqrt{y^2}?\]

Answer 15

Yes, what's the sqrt of y^2?

Answer 16

\[4\sqrt{y^2}-\sqrt{y^2}= 3\sqrt{y^2}\] am I right?

Answer 17

Not quite... go back to this: \[\Large 4\sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y} \]

What's the sqrt of y^2?

Answer 18

i don't know

Answer 19

y?

Answer 20

Think of it this way... Whats the sqrt of 4^2?

Answer 21

2

Answer 22

No... 4^2 = 16. What's the sqrt of 16?

Answer 23

4

Answer 24

So the sqrt of 4^2 is 4. What's the sqrt of y^2, then?

Answer 25

2y? ugh im confused :(

Answer 26

Well notice the sqrt of 4^2 is 4. What's the sqrt of 5^2? what's the sqrt of 2^2?

Answer 27

5,2

Answer 28

Notice the pattern? Sqrt of 4^2 = 4. Sqrt 5^2 = 5. Sqrt 2^2 = 2.

Sqrt y^2 = ...?

Answer 29

y

Answer 30

Excellent! What about the sqrt of x^2?

Answer 31

x

Answer 32

Good :) Now simplify \[\Large 4\sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y}\]

Answer 33

\[4y \sqrt{y}\]

Answer 34

Not quite but you're on the right track\[\Large 4\sqrt {y^2} \sqrt {y }-\sqrt{y^2} \sqrt {y}=\] replace the two sqrt y^2's with y
\[\Large 4y \sqrt {y }-y \sqrt {y}\]

Answer 35

\[3y \sqrt{y}\] so it's a

Answer 36

I think so, i didn't pay attention to the answer options. But good job!

Answer 37

thank you!