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Mathematics 20 Online
OpenStudy (anonymous):

You roll two dice. What is the probability that the sum of the dice is even or the sum of the dice is greater than 6? Make sure you only account for dice sums that are both even and greater than 6 once. A 6X6 table of dice outcomes will help you to answer this question. Please show me how to find the answer

OpenStudy (anonymous):

Lets make the table 1st 11 12 13 14 15 16 21 22 23 24 25 26 31 32 33 34 35 36 41 42 43 44 45 46 51 52 53 54 55 56 61 62 63 64 65 66

OpenStudy (anonymous):

36 possibilities when you roll 2 dice

OpenStudy (anonymous):

oh because it's 6*6?

OpenStudy (anonymous):

yes. now how many of these 36 possibilities are even?

OpenStudy (anonymous):

6

OpenStudy (anonymous):

oh no sorry

OpenStudy (anonymous):

18?

OpenStudy (anonymous):

oops 18 yes

OpenStudy (anonymous):

so the answer is 18?

OpenStudy (anonymous):

No you also have to figure out which pairs sum to greater than 6 16 25 26 34 35 36 43 44 45 46 52 53 54 55 56 61 62 63 64 65 66 All of these pairs sum to more than 6. There are 21 of these.

OpenStudy (anonymous):

But we double counted some. Which pairs sum to both even numbers AND numbers greater than 6?

OpenStudy (anonymous):

26 34 36 44 46 53 55 62 64 66 There are 10 of these. Final answer \[\frac{ 18+21-10 }{ 36 }\]

OpenStudy (anonymous):

Simplify that fraction and you'll have your answer

OpenStudy (anonymous):

Tough problem!

OpenStudy (anonymous):

Thank You So Much!! I'm sure I'll be able to do the next one now!

OpenStudy (anonymous):

Unfortunately, I noticed a small mistake I made...sorry. In counting the ones that are both even and greater than 6, I should have written 35 on that second line, not 34 and 36. So there are9 of those...not 10. Replace 10 with 9 in that final fraction.

OpenStudy (anonymous):

yeah I noticed... I already fixed it though

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