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x^2+25=10x
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subtract 10x from both sides
x^2+25-10x=0
Yes and now try to find 2 numbers who are added -10, and multiplied 25
hmm
-5 -5
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Very good :) now you put them in parenthesis to form a binomial
THAT'S RIGHT, I'M RIGHT @uri !!!!!!!
(x-5) (x-5)
Ye you are.
now the last step, you can simplify that to \(\sf (x-5)^2\)
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not sure how to do that.
because they're both the same
\(\sf (x-5)(x-5)=(x-5)^2\)
x^2-10x +25=0 x^2-5x-5x+25 x(x-5)-5(x-5)
(x-5) (x-5) that right?
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oh
Ye..It's right but also very wrong.
... WHAT IS RIGHT AND WHAT IS WRONG?
I AM CONFUCIOUS!
(x-5)^2 is correct
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\((x-5)^2\) is correct, not sure what @uri means with very wrong
lol it is right.
it's like (2)(2) = 2^2
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