Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

x^2+25=10x

thomaster (thomaster):

subtract 10x from both sides

OpenStudy (anonymous):

x^2+25-10x=0

thomaster (thomaster):

Yes and now try to find 2 numbers who are added -10, and multiplied 25

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

-5 -5

thomaster (thomaster):

Very good :) now you put them in parenthesis to form a binomial

OpenStudy (anonymous):

THAT'S RIGHT, I'M RIGHT @uri !!!!!!!

OpenStudy (anonymous):

(x-5) (x-5)

OpenStudy (uri):

Ye you are.

thomaster (thomaster):

now the last step, you can simplify that to \(\sf (x-5)^2\)

OpenStudy (anonymous):

not sure how to do that.

thomaster (thomaster):

because they're both the same

thomaster (thomaster):

\(\sf (x-5)(x-5)=(x-5)^2\)

OpenStudy (uri):

x^2-10x +25=0 x^2-5x-5x+25 x(x-5)-5(x-5)

OpenStudy (anonymous):

(x-5) (x-5) that right?

OpenStudy (anonymous):

oh

OpenStudy (uri):

Ye..It's right but also very wrong.

OpenStudy (anonymous):

... WHAT IS RIGHT AND WHAT IS WRONG?

OpenStudy (anonymous):

I AM CONFUCIOUS!

OpenStudy (anonymous):

(x-5)^2 is correct

thomaster (thomaster):

\((x-5)^2\) is correct, not sure what @uri means with very wrong

OpenStudy (uri):

lol it is right.

OpenStudy (anonymous):

it's like (2)(2) = 2^2

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!