What is the area of ABC (picture included)
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52.2
A couple of applications of the Pythagorean Theorem might get you there. @SanjanaP is a little low and also appears not to be aware of the Code of Conduct.
WHAT....@tkhunny
Lol im confused guys.
@SanjanaP Your answer, that you have provided with no information, is simply incorrect. I would guess that this is due to unfortunate rounding. Your answer, as it has no information, does not conform to the Code of Conduct. Click the link in the lower, left-hand side of your screen. @misszahra Do you know the Pythagorean Theorem?
no
That is quite unfortunate. Before I describe it, are you supposed to be able to solve this in some other way? Is this on a placement test?
yes
I am going to give you some reality therapy. Since you do not know this information, you should not get it correct on your placement exam. This will put you in a class where you will be exposed to the information needed to solve this problem. If you manage to solve this problem, it is possible you will be placed in a class where you are expected to know quite a bit more than you do know. This will be a very unfortunate semester or year for you. Are you SURE you want to do it right now?
please get off my post lol, your annoying and not helping at all, dismissed. @tkhunny
Well, good luck with that. I AM telling you the truth.
lol yeah thanks for that... @tkhunny i asked for help not a lecture.
It appears the help you need IS a lecture, but I defer to your judgment.
okayyyyyyyyyyyyy byeeeeee @tkhunny your old stop responding back please gosh.
Sure thing.
MissZhara, Consider the Pythagorean Theorem A^2+B^2=C^2 For triangle ABD, the hypotenuse segment AB is C^2, since the length is 9 when know the square is 9 is 81, we have C^2 then Segment BD is 7, the square of which is 49, lets call this B^2 We need to find AD, which can be derived from C^2-B^2 or 81-49=A^2 So now we have 32, lets take the square root of that which is \[4\sqrt{2}\]
thank you, so what do i do with that now
length and width of AD X BD or 7 * \[4\sqrt{2}\] or \[28\sqrt{2}\]
you have an area of a box but you only need half of this, assuming we are dealing with a right triangle, divide this value by 2
@tkhunny what are you doing lol? why aree you back?
do the same for the other side to find that area
I like @Zeno. I'm interested in what methods might do you some good. Obviously, I thought of none. I'm here to learn, too.
tk, I think you know the answer but mine is not that sophisticated :-)
So MissZ, you just need to use the pythagorean theorem to find the length of segment DC and multiply that value by 7 and don't forget to divide by 2
@Zeno Not a matter of the answer. It's a matter of reaching the student. I DO appreciate your patience.
tkhunny, I fully understand where you are coming from. I placed higher than I should have and it has not been good for me. Math is really something to be enjoyed and thought about even if it means a year in what would be considered remedial maths.
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