Question

Can someone verify:
x=(1/2)t , y=3t^3-1
=y=3/8t^3-1

Answer 1

@Psymon

Answer 2

In another problem, but I'll look in a sec:3

Answer 3

"y=3/8t^3-1" ? this is wrong

Answer 4

my options are y = three divided by eight t3 - 1

y = 24x3 - 1

y = 6x3 - 1

y = 24x - 1

@Coolsector

Answer 5

so from
x= (1/2) * t
you get
t = 2x

Answer 6

now plug it into
y=3t^3-1
what do you get ?

Answer 7

y=6x3-1?

Answer 8

no:
y= 3 * (2x)^3 - 1

Answer 9

now (2x)^3 = 2^3 * x^3 ..

Answer 10

but wouldn;t i multiply 2 and 3 to give my 6x^3?

Answer 11

but power precede multiplication

Answer 12

so 24?

Answer 13

yes

Answer 14

okay thanks!

Answer 15

yw

Answer 16

WAIT is it y=24x-1 or 24x^3-1?

Answer 17

@Coolsector

Answer 18

you can answer it.. look at (2x)^3