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y=2x^3 - 3x^2 -12x +6 find the points where the tangent is parallel to the x-axis using derivative
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Parallel to the x-axis just means taking the derivative and setting it equal to 0. Because parallel to the x-axis just means a slope of 0.
oh, i get it. thanks
Yeah, derivatives just find slope, so if you want a certain slope, just set the derivative equal to that slope. In this case the slope is simply 0. You may have not gotten there yet, but eventually you'll be asked to find criticial points, minimums and maximums. You'll be doing this same thing to find those. Setting the derivative equal to 0.
so, the answers are (-1,13) and (2,-14) am i correct?
*checks*
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Yep, you got it.
okay, :)
Yep yep :3
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