Question

Solve for c.

3abc + b = 5


c = (5 - b)/(3ab)
c = -5/3ab
c = 2 - ab\
how does one work this out

Answer 1

@dirtydan667
\[3abc+b=5\]
Subtract b from both the sides, would you try?

Answer 2

3ac=5....?

Answer 3

or 3ac=-5b

Answer 4

ok, I'll explain
\[3abc+b=5\]
Subtract b from both the sides
\[3abc+b-b=5-b\]
Now, we see on the left side there is b -b
\[3abc+\cancel b-\cancel b=5-b\]
\[3abc+0=5-b\]
Do you follow this part?

Answer 5

kinda

Answer 6

Read it again and let me know if there is a part where you have trouble

Answer 7

i read it out loud and i get it

Answer 8

ha ha :D
so we have
\[3abc=5-b\]
Now could you divide both sides by 3ab and post what would you get

Answer 9

i have no idea where to start with that sir

Answer 10

Divide both side by 3ab
\[\frac{3abc}{3ab}=\frac{5-b}{3ab}\]