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Mathematics 7 Online
OpenStudy (anonymous):

y=ax+b find the inverse and determine wether it's a function

OpenStudy (anonymous):

usually you swap y and x then solve for the new variable. y=ax+b x=ay+b Solve for y :D

OpenStudy (anonymous):

x-b over a=y but is it a function

OpenStudy (anonymous):

y = (x-b)/a

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Well I can tell you it is a function since the inverse of a linear function is usually a linear function too so it is a function :P

OpenStudy (ybarrap):

Take this new y function and put it in for x in the original equation you should get x back if this is an inverse

OpenStudy (ybarrap):

If an equation has an inverse then it's a function

OpenStudy (anonymous):

Is y=2 a function or x=9/y a function

OpenStudy (ybarrap):

Try it. Y=2 exchange x and y

OpenStudy (ybarrap):

Then take the result and put in for x

OpenStudy (ybarrap):

Do you get x back?

OpenStudy (ybarrap):

What? No x? That should be a clue

OpenStudy (ybarrap):

Does this make sense?

OpenStudy (ybarrap):

Your second one has an inverse.

OpenStudy (ybarrap):

The reason an inverse is a function is because it is bijective. http://en.wikipedia.org/wiki/Function_(mathematics)#Injective_and_surjective_functions

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