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OpenStudy (anonymous):
y=ax+b find the inverse and determine wether it's a function
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OpenStudy (anonymous):
usually you swap y and x then solve for the new variable.
y=ax+b
x=ay+b
Solve for y :D
OpenStudy (anonymous):
x-b over a=y but is it a function
OpenStudy (anonymous):
y = (x-b)/a
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Well I can tell you it is a function since the inverse of a linear function is usually a linear function too so it is a function :P
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OpenStudy (ybarrap):
Take this new y function and put it in for x in the original equation you should get x back if this is an inverse
OpenStudy (ybarrap):
If an equation has an inverse then it's a function
OpenStudy (anonymous):
Is y=2 a function or x=9/y a function
OpenStudy (ybarrap):
Try it. Y=2 exchange x and y
OpenStudy (ybarrap):
Then take the result and put in for x
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OpenStudy (ybarrap):
Do you get x back?
OpenStudy (ybarrap):
What? No x? That should be a clue
OpenStudy (ybarrap):
Does this make sense?
OpenStudy (ybarrap):
Your second one has an inverse.
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