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solve x^2-4x=5
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this can be solved by factoring rewrite the equation by subtracting 5 from each side of the equation. so you have \[x^2 -4x -5 = 0\] now you can factor the quadratic
I don't know how to factor
use the quadratic formula then
and learn how to factor
a quadratic equation has the form: ax^2 + bx + c to solve for x, make the equation equal 0 ax^2 + bx + c = 0 then use the quadratic formula to find the answer (see attached image for quadratic formula) in this case your equation is: x^2 −4x −5 =0 ax^2 + bx + c = 0 which means that for this equation: a = 1 b = -4 c = -5 so sub ur values for a b and c into the quadratic formula, and is should give you 2 values which satisfy when x=0
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