Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (–2, – 16), and x intercepts at x = –6 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 4x − ___ Help me on this one it's hard

Answer 1

some help me please

Answer 2

@Machida

Answer 3

@Ryaan

Answer 4

do u guys know how to do this?

Answer 5

@Hero , @.Sam. , @ganeshie8 , @ash2326

Answer 6

thanks @Machida

Answer 7

ugh i need help

Answer 8

If it has x-intercepts at -6 and 2, then just multiply (x + 6)(x - 2) to figure out the quad

Answer 9

If the vertex is (–2, – 16),
Then
\[y=(x+2)^2-16\]

Answer 10

Vertex=(A,B)
\[y=(x-A)^2+B\]