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Mathematics 20 Online
OpenStudy (anonymous):

In the triangle below, determine the value of a.

OpenStudy (anonymous):

|dw:1376242173339:dw|

OpenStudy (anonymous):

First find the length of side AB.

OpenStudy (anonymous):

okay, how would you do that?

OpenStudy (anonymous):

So use sin cos or tan to solve for AB Than use Pythagorean theorem. \[a ^{2} + b ^{2} = c ^{2}\] a is the shortest side and c is the hypotenuse.

OpenStudy (anonymous):

The 43= 43 degrees by the way... :)

OpenStudy (anonymous):

and okay one sec

OpenStudy (anonymous):

Yeah I know. So you have 2 angles 43 and 90.

OpenStudy (anonymous):

yeah?

OpenStudy (jdoe0001):

http://www.mathwords.com/s/s_assets/s126.gif

OpenStudy (anonymous):

Find if your using sin cos or tan. put the 43 in and find AB and use Pythagorean to solve

OpenStudy (anonymous):

okay so I would be using sin for this right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I got something close to 4.09... is that correct?

OpenStudy (anonymous):

sin 43 = a/6 so a = 6sin 43 set up using what's given and a trig. function that inculdes those things.

OpenStudy (anonymous):

I got 4.09 again...:(

OpenStudy (anonymous):

yeah, that's what it is. it's just more direct using the trig ratios. you can do the pythagorean thm but it's a longer route to get what you want and besides, you used the trig funtions anyways.

OpenStudy (anonymous):

ok thankyou :)

OpenStudy (anonymous):

you're welcome

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