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Mathematics 24 Online
OpenStudy (anonymous):

HELP: Determine the values of where the tangent line is horizontal for the function:

OpenStudy (anonymous):

OpenStudy (zzr0ck3r):

take the derivative, and set it equal to zero

OpenStudy (anonymous):

then plug into original function?

OpenStudy (zzr0ck3r):

nope, it wants x values, so solve for = 0, and that's your answer

OpenStudy (anonymous):

oh ok.

OpenStudy (zzr0ck3r):

example f(x) = x^2 + 2x f'(x) = 2x+2 2x+2 = 0 x = -1 so f(x) has horizontal tangent at x = -1

OpenStudy (anonymous):

@zzr0ck3r thank you=]

OpenStudy (zzr0ck3r):

np

OpenStudy (zzr0ck3r):

I will note that in most cases when they say "value" that implies y, but in this situation they said "x value".

OpenStudy (anonymous):

to take the derivative: we must use the power and quotient rule for this question right?

OpenStudy (anonymous):

i missed up on something, hats not coming out right..

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