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HELP: Determine the values of where the tangent line is horizontal for the function:
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take the derivative, and set it equal to zero
then plug into original function?
nope, it wants x values, so solve for = 0, and that's your answer
oh ok.
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example f(x) = x^2 + 2x f'(x) = 2x+2 2x+2 = 0 x = -1 so f(x) has horizontal tangent at x = -1
@zzr0ck3r thank you=]
np
I will note that in most cases when they say "value" that implies y, but in this situation they said "x value".
to take the derivative: we must use the power and quotient rule for this question right?
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i missed up on something, hats not coming out right..
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