Mathematics
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OpenStudy (anonymous):
x+y=0
3x-3y=0
(-1,1)
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OpenStudy (anonymous):
yes that is correct because when u plug in the point into the function you get 0=0
OpenStudy (anonymous):
i get -1=0,-6=0
OpenStudy (anonymous):
no you get -1+1=0 when you plug in the coordinates to the first function and for the second you get 3(-1)-3(1)=0 you get 0=0.
OpenStudy (anonymous):
there both true because left side =right side.
OpenStudy (anonymous):
i thought 3(-1) =-3
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OpenStudy (anonymous):
this what i did 3(-1)-3(1)=0
-3-3=0
-6=0
OpenStudy (anonymous):
sorry @jinan you right i forgot about the other negative for the second function. So the top function is true and the one below it is false.
OpenStudy (anonymous):
x+y=0 this what i get for this one
-1+1=0
-1=0
(-1,1)
OpenStudy (anonymous):
is that correct
OpenStudy (anonymous):
no that one is not correct because they cancel each other out. -1+1 =0
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OpenStudy (anonymous):
-1+1=0
0=0
OpenStudy (anonymous):
ok you are right that you so much
OpenStudy (anonymous):
your welcome! @jinan
OpenStudy (anonymous):
do you know anything about graphing
OpenStudy (anonymous):
i have two questions for graphing
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OpenStudy (anonymous):
what are the question?
OpenStudy (anonymous):
-x+y=1
x+y=0
OpenStudy (anonymous):
graph the linear
OpenStudy (anonymous):
sorry that wasnt right
OpenStudy (anonymous):
-x+x=-2x right????????
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OpenStudy (anonymous):
y+y=2y
OpenStudy (anonymous):
im not sure
OpenStudy (anonymous):
hod on i'm trying to solve it right now. give me a minute.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
do u have an idea on how you graph is suppose to look?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
|dw:1376262279862:dw| does that look familiar