Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (texaschic101):

I am feeling stupid right now.....can somebody check this for me :)

OpenStudy (texaschic101):

The sum of 2 consecutive integers is less then 83.Find the pair of integers with the greatest sum. This is what I did... x + x + 1 < 83 2x < 82 x < 41 so would my integers be 39 and 40 ?

OpenStudy (anonymous):

if its less than 41, it would be any number that is 40 or under 40, wont it?

OpenStudy (texaschic101):

the two numbers closest to 41 are 39 and 40.....so wouldn't that be the answer

OpenStudy (texaschic101):

because one number is x and the other is x + 1

OpenStudy (texaschic101):

so do you think 39 and 40 are the answers ?

OpenStudy (texaschic101):

@zepdrix .....check this please

OpenStudy (texaschic101):

they would have to be wouldn't they ?

OpenStudy (texaschic101):

although 40 and 41 = 81......

OpenStudy (anonymous):

that would equal 79, and if the two numbers have to be under 41, and have a sum of less than 83, then yes. but

OpenStudy (texaschic101):

do I even need the inequality ? Or just add 2 numbers, and as long as they are consecutive and less then 83

OpenStudy (anonymous):

ya i think you just add 2 numbers that are consecutive and under 83

OpenStudy (texaschic101):

so 41 and 42

OpenStudy (anonymous):

i did that, but that equals 83, its not under 83..

OpenStudy (texaschic101):

no wait...it is less then 83.....40 and 41

OpenStudy (anonymous):

so ya :)

OpenStudy (anonymous):

40 and 41

OpenStudy (texaschic101):

I was told to set up an inequality, but when I did that, I got x < 41....so I got confused

OpenStudy (anonymous):

http://answers.yahoo.com/question/index?qid=20120822062248AAARlQE it is asked here, but not solved. it is like number 5 however.. are those also problems you have? maybe this will help :)

OpenStudy (anonymous):

did that help?

OpenStudy (texaschic101):

yes it did...thank you so much :)

OpenStudy (texaschic101):

I wish they would have had the answer to the one I am doing now

OpenStudy (anonymous):

good! :) do you think you can help me with a problem please? have have been trying to solve it for hours. Literally!

OpenStudy (texaschic101):

I can try...is it posted ?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

OpenStudy (texaschic101):

(35 + 37 + 42 + 57 + 61 + 70) / 6 = 302/6 = 50.33 35 - 50.33 = -15.33^2 37 - 50.33 = - 13.33^2 42 - 50.33 = -8.33^2 57 - 50.33 = 6.67^2 61 - 50.33 = 10.67^2 70 - 50.33 = 19.67^2 now add the squares... (3.92 + 3.65 + 2.89 + 2.58 + 3.27 + 4.44) / 6 = 20.75/6 = 3.45 I did something wrong....I am way off

OpenStudy (anonymous):

ive been trying to figure out your problem. i found another problem like it but different numbers. http://answers.yahoo.com/question/index?qid=20110110221921AA77LEC so it would be 2x+1<83 2x<83-1 2x<82 x<41 the largest integer that is less than 41, is 40. and the next consecutive integer is 41. so it would be 40+41<83 which would come out to 81<83

OpenStudy (texaschic101):

but I thought it had to be less then 41

OpenStudy (anonymous):

look at what they did

OpenStudy (anonymous):

thanks! i did all that, but didnt divide by 6. why do you divide by 6 twice?

OpenStudy (texaschic101):

check this out...... http://easycalculation.com/statistics/standard-deviation.php

OpenStudy (texaschic101):

your answer is 14.3

OpenStudy (anonymous):

omg thank you!

OpenStudy (texaschic101):

at first I was going by this... http://www.mathsisfun.com/data/standard-deviation.html

OpenStudy (anonymous):

wouldnt it be variance tho, not standard variation?

OpenStudy (anonymous):

or is it the same?

OpenStudy (anonymous):

ya, i saw that.. thats what i was trying too.

OpenStudy (texaschic101):

I am not sure...look at the calculator link....there are many things listed....I really don't know

OpenStudy (texaschic101):

did you get anywhere close to 14.3 ?

OpenStudy (texaschic101):

mine was way off

OpenStudy (anonymous):

same! i got 1.74....

OpenStudy (texaschic101):

well..I got 3.45.....I had to do a lot of rounding....either way I was way off

OpenStudy (anonymous):

got it!! finally! i used that calculator and variance is standarvariation^2 so i just plugged in the standard variation and its 205.4... which is what it says

OpenStudy (texaschic101):

I know you have to find the mean by adding all the numbers and dividing by how many numbers there are. Then you subtract that answer from every number and square it. Then you add the squared numbers and divide by how many numbers there are. I always hated these kind of problems

OpenStudy (texaschic101):

oh my......check this calculator out...I o not think 14.3 is the answer http://www.miniwebtool.com/sample-variance-calculator/

OpenStudy (texaschic101):

typo * do

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

ive been getting them wrong, i think im gunna fail this part :/

OpenStudy (texaschic101):

I am sorry I can't help more....I am not so good at them either, as you can tell

OpenStudy (anonymous):

noo! its not your fault! dont worry! you were great help earlier (and even now) thank you! your really smart :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!