Question

Solve for t: 3t^2 - t =2
A. t= 3,2
B. t= 1/2, 1
C. t= -2/3,1
D. t= -1/2,1

Answer 1

we want the form \[at^2+bt+c=0\]
we have
\[3t^2-t=2\\\downarrow\\3t^2-t-2=0\]
we want two numbers that multiple to a*c=3*-2=-6 but we want these same two numbers to add to b = -1
what are two such numbers?

Answer 2

I'm not understanding how you find these numbers.

Answer 3

transpose 2 to the left side, then factor the equation.

Answer 4

3t^2-t-2=0

Answer 5

the factor it using quadratic equation or any method that's easier for you.
quadratic equation: