Question

ues the method of substitution to solve the system of linear equations.
2x-y=6
7x-3y=23

Answer 1

multiply eqn #1 by -3--> you have -6x+3y=-18. Then add the eqn 2 and the new eqn you get x=5. from either of the original eqns, you can get y.

Answer 2

im lost

Answer 3

if we multiply first equation with -3
\[2x-y=6 --> -6x+3y=-18\]
Now we are going to add the -6x+3y=-18 dude with 7x-3y=23.
You will then have x= 23-18=5.

you know that 2x-y=6, and you also know x=5. So you can find y to be 4.

Answer 4

you lost me