Question

Please Help ! Fan + Medal !

Posted Below

Answer 1

(2x-1) is common to bother the numerator and denominator of f(x)/g(x). You are left with x in the numerator.

Answer 2

The correct answer is D.

Answer 3

@SwiftDrift Explain Please ?

Answer 4

hold on let me double check

Answer 5

Your fundamental understanding of algebra is flawed.

Answer 6

So It's D?

Answer 7

Yes, stand by for explanation.

Answer 8

wow -_- thxs for letting me know
;p jk. btw sorry for wrong work/answer

Answer 9

f(x) = x(2x-1)
g(x) = 2x - 1

\[\frac{ f(x) }{ g(x) } = \frac{ x(2x - 1) }{(2x - 1) }\]

We have (2x - 1) on both top and bottom. Anything divided by itself is 1, so we can eliminate common terms from the numerator and denominator. We are left with x in the numerator.

Answer 10

Thanks :)