A photo is 6 inches long. Kamala enlarged the photo so that it is twelve inches long. By keeping the same proportion of the photo, what would be the width of the photo if the enlarged photo is 8 inches wide?
@abb0t
so lets call W-the new width , L - the new length w - the old width and l - the old length you know W=8,L=12 and l=6
now you know since they kept the same proportion of the photo: W/L = w/l w = l*W/L
can you do it now ?
No
just plug in the numbers.
I don't understand
"so lets call W-the new width , L - the new length w - the old width and l - the old length you know W=8,L=12 and l=6 " this is fine ?
So the new width is 16
no, W/L = w/l w = l*W/L
W/L is the new proportion and w/l is the old proportion
I am so lost
the proportions are equal so W/L = w/l now you have to isolate w and plug in the values of W, L and l
you KNOW the new width .. they ask you what is the width before
ok I understant that part
so, you know W,L and l you want to find w. since the proportions are equal W/L = new proportion w/l = old proportion -> w/l = W/L
agree ?
Yes
so, w/l = W/L multiply both sides by l w = W*l/L w=8*6/12=4
are you there ?
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