Question

factor completely:
see below:

Answer 1

\[2a ^{2}-2ab+3ac-3bc\]

Answer 2

Note the pattern 2,-2, 3,-3 which helps you to factor by grouping.

Answer 3

its not coming to me

Answer 4

its wrong

Answer 5

i see 2 a
2 b
2 c's I dont get it

Answer 6

What if we try:
\(2a^2-2ab+3ac-3bc\\
=2a(a-b) + 3c(a-b)
\\
\)

Answer 7

Just regroup it again

Answer 8

Factor out the common factor (a-b) and you'll have it.

Answer 9

we have the same answer @mathmate

Answer 10

ok common factor??
walk me through it please.
how did you find common factor??

Answer 11

I guess we should, especially in math! :)

Answer 12

Something like this:
16-12
=4*4 - 4*3
=4(4-3)